0=2000-16t^2

Solution for 0=2000-16t^2 equation:

0=2000-16t^2

We move all terms to the left:

0-(2000-16t^2)=0

We add all the numbers together, and all the variables

-(2000-16t^2)=0

We get rid of parentheses

16t^2-2000=0

a = 16; b = 0; c = -2000;
Δ = b2-4ac
Δ = 02-4·16·(-2000)
Δ = 128000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{128000}=\sqrt{25600*5}=\sqrt{25600}*\sqrt{5}=160\sqrt{5}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-160\sqrt{5}}{2*16}=\frac{0-160\sqrt{5}}{32}
=-\frac{160\sqrt{5}}{32}
=-5\sqrt{5}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+160\sqrt{5}}{2*16}=\frac{0+160\sqrt{5}}{32}
=\frac{160\sqrt{5}}{32}
=5\sqrt{5}
$